Solenoid Inductance Calculator

The free Solenoid Inductance Calculator tool makes it simple and quick to calculate a solenoid's self-inductance. To check the inductance as output, enter the length, cross-section area, radius, and the number of turns data, then press the calculate button.

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Number of turns(N):

Solenoid Inductance Calculator: This user-friendly calculator makes calculating the self-inductance of a solenoid simple. This calculator tool provides an instantaneous and accurate solution, as well as thorough calculations to solve the problem. Find out how to calculate inductance and the solenoid inductance formula in this step-by-step guide. You can also discover examples of questions and relevant information regarding solenoids on this page.

Inductance of a Solenoid

The RLC Circuit uses a solenoid, which is a coil. The internal element is the characteristic inductance. The self-induced potential difference describes how current flows through a coil.

The voltage in a solenoid is equal to the ratio of potential to current change rate. V = -L x dI/dt

A solenoid's inductance can be expressed as L = µ₀ x N^2 x A/l

  • Where, L = self-inductance of a solenoid
  • N = number of turns
  • r = coil radius
  • A = cross-sectional area of the solenoid
  • l = length
  • µ₀ = vacuum permeability (µ₀ = 1.25664 x 10^-6 T*m/A)

How do you find the Inductance of a Solenoid?

The steps for calculating the self-inductance of a solenoid are listed below

  • Step 1: Check the solenoid's number of turns, radius, and length.
  • Step 2: Calculate the cross-sectional area using the solenoid's radius.
  • Step 3: Multiply the cross-section area and vacuum permeability by the square of the number of turns.
  • Step 4: To calculate the inductance of a solenoid, multiply the product by the length of the solenoid.

How to Use the Solenoid Inductance Calculator?

The following is the procedure how to use the solenoid inductance calculator

  • Step 1: Input the unknown value's length, cross-section area, radius and number of turns, and x in the appropriate input fields.
  • Step 2: To acquire the result, click the "Calculate the Unknown" button.
  • Step 3: Finally, the output field will show the self-inductance of a solenoid.

Examples on Calculating Inductance of a Solenoid

Question 1: A solenoid has 43 turns and can carry 4 amps of current. Find the inductance of a circle with a radius of 7 cm and a length of 8 cm?


Given: Number of turns of solenoid N = 43

Radius r = 7 cm

Length l = 9 cm = 0.09 m

Cross section area A = πr²

A = π x 7 x 7

= 153.93 cm^2 = 0.001539 m^2

Inductance of the solenoid L = µ₀ x N^2 x A/l

= 1.25664 x 10^-6 x 43² x 0.001539/0.09

= 39.73 x 10^-6 µH

Therefore, the inductance of a solenoid is 39.73 x 10^-6 µH.

For more concepts check out to get quick answers by using this free tool.

FAQs on Solenoid Inductance

1. Is a solenoid an inductor?

An inductor is a solenoid. Not all solenoids are inductors. A solenoid is a moving coil with a ferrous core. A wire coil with a fixed core, which may or may not be present, is known as an inductor.

2. What is the coil's inductance?

Even a straight piece of wire has some inductance, which is the name given to the property of a component that opposes the change of current passing through it.

3. How does the number of turns in a solenoid's coil affect its self-inductance?

The coil's self-inductance is determined by the cross-sectional area, the number of turns per unit length, the length of the solenoid, and the permeability of the core material.

4. Why is an electromagnet stronger than a solenoid?

Inside the solenoid, a magnetised ferromagnetic substance adds to the strength of the magnetic field created by the current alone.

5. How does the solenoid inductance calculator work?

The inductance of a solenoid calculator quickly calculates the inductance of a coil by entering the required information, such as the number of turns, radius, cross-sectional area, and length.

6. What is the significance of self-inductance?

The electrical energy is stored in the form of a magnetic field by the inductor. Filters, sensors, induction motors, chokes, turning circuits, transformers, ferrite beads, and relays all use self-inductance.