Use the Shockley Diode Calculator to quickly determine the voltage drop or current flow in a genuine diode by entering thermal voltage, saturation current, and other parameters. Simply insert the emission coefficient, current, saturation current, and thermal voltage into the calculator's fields to get a quick result.
Shockley Diode Calculator: Do you want to know how to calculate the voltage in a real diode? Don't worry, we've got you covered with our free Shockley Diode Calculator. This calculator gives you the exact results as well as a step-by-step solution. In the sections below, you'll find a full description of how to find the current flowing through a diode as well as the Shockley diode equation. Continue reading to learn what a true diode is and how to answer Shockley diode questions.
A diode is an electrical component that enables just one direction of the current passage. To allow current to flow in one direction, a p-n junction is needed. The I-V relationship is discovered by using the Shockley diode (Current and Voltage). For ideal and real (imperfect) diodes, the Shockley diode equation can be utilized.
The diode law is another name for it. Two terminals, three junctions, and a four-layer semiconductor device make up a Shockley diode, also known as a PNPN diode. It's like a thyristor with a gate that can be detached. The diode equation of Shockley is as follows I = Is x ( e^(Vd/n x Vt) - 1)
Here is a simple step-by-step procedure for calculating the amount of current passing through a genuine diode, as well as the voltage drop. Follow these instructions then you'll have no difficulty answering the questions.
The following is the procedure how to use the Shockley Diode calculator
Question 1: The saturation current of an ideal diode is 20 A, the thermal voltage is 150 V, and the voltage drop is 180 V. Using the Shockley diode equation, what is the current going through the diode?
Solution:
Given: Is = 20 A
Vt = 150 V
n = 1
Vd = 180 V
Shockley diode equation I = Is x ( e^(Vd/n x Vt) - 1)
Substitute the given values
I = 20 x (e180/1 x 150 - 1)
= 20 x (e^1.2 - 1)
= 20 x (3.320 - 1)
= 20 x 2.320
= 46.40
Hence, the current flowing through the ideal diode is 46.40 A.
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1. What is the purpose of a Shockley diode?
Shockley diodes are mostly used in switching circuits. The relaxation oscillator and trigger switch are the two most common applications of the Shockley diode.
2. Is there a difference between a Shockley and a Schottky diode?
Shockley diode is a semiconductor-coupled diode with two PN junctions, whereas Schottky diode is a metal-semiconductor junction diode. Shockley is a power source, a switching device, and an inorganic solar cell all in one. The Schottky diode is a signalling and rectification device.
3. How do you put a Shockley diode to the test?
Connect the anode of the Schottky diode to the red positive test wire, and the cathode of the diode to the black common test lead. A "beep" or "buzz" from the multimeter should be heard. The multimeter will make a tone if the Schottky diode responds as expected.
4. What does a Shockley diode do?
A Shockley diode is a diode that is mostly used for switching purposes. The Shockley diode, unlike other types of semiconductor diodes, features more than one PN junction. It's made up of two of each type of semiconductor arranged in an alternating pattern.
5. In terms of operation, how does a Shockley diode vary from a Schottky diode?
Shockley is a power source, a switching device, and an inorganic solar cell all in one. The Schottky diode is a signalling and rectification device. Because the Schottky diode's barrier is too small, it can run at a higher frequency or with a faster response while using less power.