Projectile Motion's Maximum Height Calculator is a free online tool that estimates the projectile's maximum height. It uses velocity, initial height, and launch angle as inputs to compute the projectile maximum height in a jiffy.
Maximum Height of Projectile Motion - Formulas
Maximum Height of Projectile Motion describes how a body that is hurled or projected into the air diagonally near the earth's surface goes along a curving path of constant acceleration directed toward the earth's centre. The path that the object takes is known as projectile motion.
When the projectile reaches 0 vertical velocity, it reaches its maximum height. As a result, the velocity vector's vertical component will point downwards. The range of the projectile is its horizontal displacement, which is determined by the object's initial velocity.
When the object is released from the ground (with an initial height=0), hmax = Vo┬▓ * sin(╬▒)┬▓ / (2 * g)
When starting up an object from a height (initial height > 0), hmax = h + Vo┬▓ * sin(╬▒)┬▓ / (2 * g)
- Where, Vo is the initial velocity
- ╬▒ be the angle of launch
- h be the initial height
- hmax be the maximum height
How can you figure out what a projectile's maximum height is?
The stages to determine the maximum height of a projectile are as follows. Go over these stages again and again, paying close attention to what you're doing.
- Step 1: Get the object's initial height, initial velocity, angle of launch from the specified question.
- Step 2: Multiply the square of the initial velocity with the sine of the angle square.
- Step 3: The acceleration due to gravity, which is 9.81m/s, is doubled.
- Step 4: Divide theresult in step 2 with the result in setp 3.
- Step 5: Add the result to the initial height.
- Step 6: The highest height of the projectile motion is the result obtained.
For more concepts check out physicscalculatorpro.com to get quick answers by using this free tool.
Maximum Height in a Projectile Motion Examples
Question 1: A fireman jet pours a hosepipe upwards at a skyscraper fire. The water is leaving the hose at a speed of 38m/s with the initial height of 43m. If the fireman holds the hose at a 23┬░ angle. Estimate the water flow's maximum height.
Consider the problem, we have the following are the input values:
Initial velocity Vo=38 m/sec
Initial height, h=43m
An angle of launch ╬▒ = 23┬░
We know that, An acceleration due to gravity, g = 9.8 m/sec┬▓
hmax = h + Vo┬▓ * sin(╬▒)┬▓ / (2 * g)
hmax = 43+(38)┬▓*sin(23┬░)┬▓/(2*9.8)
Therefore, the maximum height hmax=54.24m
FAQs on Projectile Motion Maximum Height Calculator
1. In a projectile motion, how do you reach the maximum height?
The subtle formula for determining the maximum height of a projectile motion, hmax = (h+ Vo2*sin(╬▒)2)/2 * g . Learners must calculate the launch angle, initial velocity, and initial height and then substitute them into the provided formula. Obtain the maximum height of the projectile motion using the equations.
2. When it comes to projectile motion, does height matter?
Yes, the projectile's trajectory is affected by the object's height. The horizontal displacement increases as the height of release increases, regardless of the release speed or angle.
3. How do you calculate the projectile's maximum height using a calculator?
- Students should enter projectile motion parameters such as initial height, angle of launch, and initial velocity into the relevant input sections of the Maximum height calculator.
- To acquire the maximum height as an output in a fraction of a second, press the calculate button.
4. What is the definition of projectile motion?
A projectile is a flying object that has been thrown or projected into the air. Probably the main acceleration acting in the vertical direction in projectile motion is the acceleration owing to gravity. Football, baseball, cricket, and some other sports are examples.