Ideal Transformer Calculator

There are two coils in a transformer: primary and secondary coils. A changing magnetic field is created by the AC current passing through the transformer primary coil. In the secondary coil, the magnetic field causes a voltage difference and electromotive force. The magnetic field is responsible for transferring energy from one circuit to the next.

The number of windings in the primary and secondary coils in relation to each other. The strength of the magnetic field is determined by the number of windings in the primary coil, whereas the strength of the electromotive force is determined by the secondary coil.

In the ideal transformer, there is no power loss. The output power generated here is the same as the input power. The ideal transformer equation, which connects primary and secondary voltages, is as follows

Secondary Voltage Vs = Vp x Ns/Np

Primary Voltage Vp = Vs x Np/Ns

Secondary Winding Ns = Vs x Np/Vp

Primary winding Np = Vp x Ns/Vs

The current equation is Ip * Vp = Is * Vs

Compute the voltage or widths of the ideal transformer with ease by following these easy procedures and guidelines.

• Step 1: Check the primary and secondary windings, as well as the primary voltage.
• Step 2: Multiply the voltage of the primary winding by the voltage of the secondary winding.
• Step 3: To find the secondary voltage, divide the product by the primary voltage.

This transformer calculator makes it simple to compute the transformer's primary and secondary full-load currents. The transformers turn ratio and type are also determined through this parameter.

• Get the necessary information, such as voltage, current, thickness, and magnetic field.
• Multiply the conductor thickness from the voltage.
• Calculate the hall coefficient by multiplying the result by the product of the current and magnetic field.

For more concepts check out physicscalculatorpro.com to get quick answers by using this free tool.

Question 1: A transformer's primary and secondary windings have 1700 and 1200 turns, respectively. Find the optimal transformer secondary voltage if the primary voltage is 200 V?

Solution:

Given:

Transformer Primary Winding Np = 1700

Transformer Secondary Winding Ns = 1200

Transformer Primary Voltage Vp = 200 V

Ideal transformer secondary voltage formula is;

Vs = Vp x Ns/Np

Vs = 200 x 1200/1700

= 141.17

Hence, the ideal transformer secondary voltage is 141.17 V.

Question 2: A transformer has 1800 loops in the primary coil and 1200 loops in the secondary coil. What is the current in the secondary coil if the primary coil current is 6 Ampere?

Solution:

Given:

Primary coil (N1) = 1800 loops

Secondary coil (N2) = 1200 loops

The current flowing through the primary coil (I1) = 4 A

I2/I1 = N1/N2

I2/4 = 1800/1200

I2 = 6A

The current on the secondary coil is 6 Ampere.

1. What is the ideal transformer?

An ideal transformer is a hypothetical transformer that has no losses, such as core losses, copper losses, or other transformer losses. This transformer has a 100% efficiency rating.

2. What are the signs of a bad transformer?

HVAC Humming And Vibrating Symptoms of a Bad Transformer - The sound of transformers humming as usual. Tripped Circuit Breaker - When your HVAC unit's transformer fails, the circuit breaker will typically trip.

3. What are the ideal transformer's characteristics?

The two transformer windings have a low resistance, which is one of the attributes of ideal transformers. The transformer's efficiency is 100 %, and the total flux generated has a confined core that links to the windings. There is no flux or inductance leakage.

4. What is the transformer's primary function?

A transformer is a type of electrical equipment that lowers the voltage. Magnetic induction is used to power these devices. Its mechanism of operation is based on the mutual inductance of two circuits connected by a shared magnetic flux.

5. How many ohms should a transformer read?

The ohmmeter should show a closed circuit or 0 ohms. Connect the ohmmeter's leads to the high side of the transformer's leads. A resistance reading should be detected by the metre.