The Gay-Lussac Law Calculator is an easy-to-use application that uses initial and final parameters to get an unknown answer quickly. This calculator tool provides quick results and critical information on basic gas characteristics during an isochoric transition.
Gay-Lussac’s Law Calculator: Having trouble learning Gay-Lussac’s Law? Then you've come to the right place. This page contains information such as why Gay-Law Lussac's is used, its formula, and sample problems. Also, learn how to use Gay-Law Lussac's to compute the unknown properties of a gas step by step.
When there is a constant amount of gas in a closed and rigid container, Gay-law Lussac's (also known as the pressure law) states the relationship between pressure and temperature. According to the law, the absolute pressure is exactly proportional to the temperature.
The gas container must be made in such a way that the volume of the gas remains constant under any condition for Gay-law Lussac's to hold true. To put it another way, Gay-law Lussac's describes how an ideal gas behaves throughout an isochoric (constant-volume) process.
Gay-Lussac's law formula can be stated as follows P1T2 = P2T1
For more concepts check out physicscalculatorpro.com to get quick answers by using this free tool.
To determine the unknown parameters of Gay-Law Lussac's in a fraction of a second, follow the easy instructions below.
The procedures for using the calculator based on Gay Lussac's Law to find the unknown quantity are given here.
According to the International Union of Pure and Applied Chemistry (IUPAC): Standard Temperature and Pressure (STP), p₀ = 10⁵ Pa, T = 0 °C;
Is it possible to see how Gay-Lussac's Law operates in our daily lives? Consider the following examples:
Question 1: When a gas in a cylinder is heated to 750 K, the pressure in the cylinder is 5.5 atm. If the gas's original pressure was 2.5 atm, what was its initial temperature?
Initial pressure P1 = 2.5 atm
Final pressure P2 = 5.5 atm
Final temperature T2 = 750 K
Gay-Lussac’s Law, P1T2 = P2T1
T1 = (P1T2)/P2
= (2.5 * 750)/5.5
Hence, the initial temperature of the gas in the cylinder = 340.9 K.
Question 2: The pressure of the gas in deodorant is 5 atm at a temperature of 450 K. What was the gas's pressure when it was heated to 1500 K?
Initial pressure P1 = 5 atm
Initial temperature T1 = 450 K
Final temperature T2 = 1500 k
final pressure P2 = (P1T2)/T1
= (5 * 1500)/450 = 7500/450 = 16.67
Final Pressure = 16.67
1. How does Gay-Lussac's Law is calculated?
When the volume of a given mass of gas remains constant, Gay-Law Lussac's asserts that the pressure varies directly with the Kelvin temperature. P1/T1=P2/T2 is the Gay-Lussac's Law formula.
2. What are the two factors covered by Gay-Lussac's law?
According to Gay-or Lussac's Amonton's law, the absolute temperature and pressure of an ideal gas are directly related under conditions of constant mass and volume. To put it another way, heating gas in a sealed container increases its pressure, but cooling a gas decreases its pressure.
3. What is the Law of Gay Lussac?
According to Gay Lussac's law, the temperature of a gas of fixed mass and volume is directly proportional to its pressure.